All 2-digit primes are odd so their difference MUST be even.
I make it 97 - 11 = 86
Very interesting, but you appear to have put the word "prime" into a question that did not contain it.
Sloppiness cannot be tolerated.
The largest 4-digit number is 9999, while the smallest 4-digit number is 1000. To find the difference between them, you subtract the smallest number from the largest: 9999 - 1000 = 8999. Therefore, the difference between the largest and smallest 4-digit numbers is 8999.
9999
The smallest number is 5,789. The largest is 98,750. The difference is 92,961.
9888
The smallest is 11 and the largest is 97.
The largest 5-digit number is 99,999, the smallest is .00001,and the difference is 99,998.99999 .If you only want to consider whole numbers, then the smallest is 10,000and the difference is 89,999 .
The largest 4-digit number is 9999, while the smallest 4-digit number is 1000. To find the difference between them, you subtract the smallest number from the largest: 9999 - 1000 = 8999. Therefore, the difference between the largest and smallest 4-digit numbers is 8999.
9999
86
The smallest number is 5,789. The largest is 98,750. The difference is 92,961.
Sum = 109 Difference = 89
9888
9999 - 102 = 9897
what is the difference between the largest 8-digit number and the smallest 6-digit number
The smallest is 11 and the largest is 97.
9999-1023 = 8976
The smallest digit (not including 0) is 1, the largest is 9 ((in the decimal system). The difference is 9 - 1 = 8