All 2-digit primes are odd so their difference MUST be even.
I make it 97 - 11 = 86
Very interesting, but you appear to have put the word "prime" into a question that did not contain it.
Sloppiness cannot be tolerated.
9999
The smallest number is 5,789. The largest is 98,750. The difference is 92,961.
9888
The smallest is 11 and the largest is 97.
The smallest two digit number is 00 (a number used as a wire gauge) and the largest is 99, so the difference between the largest and smallest 2-digits numbers is 99 (99 - 00)
The largest 5-digit number is 99,999, the smallest is .00001,and the difference is 99,998.99999 .If you only want to consider whole numbers, then the smallest is 10,000and the difference is 89,999 .
9999
86
The smallest number is 5,789. The largest is 98,750. The difference is 92,961.
Sum = 109 Difference = 89
9888
9999 - 102 = 9897
what is the difference between the largest 8-digit number and the smallest 6-digit number
The smallest is 11 and the largest is 97.
9999-1023 = 8976
The smallest digit (not including 0) is 1, the largest is 9 ((in the decimal system). The difference is 9 - 1 = 8
If leading zeros are not allowed to make the numbers, then largest = 9876, and smallest = 1023. To get the difference, just subtract: 9876 - 1023 = 8853