-x*4*cos4x + (-1)*sin4x = -4xcos(4x) - sin(4x)
4x * x = 4x^2
The differentiation of sin x plus cosx is cos (x)-sin(x).
( u(x+h) - u(x) )/ h
ANSWER: -4X2 -8X-4x (x+2)= (-4x * x) + (-4x*2)= -4X2 -8X
Say you have y=x2 -4x +4 y=(x-2)(x-2) x*x=x2 x*-2=-2x -2*x=2x -2*-2=4 x2 -4x +4
4x^4 or 4x*4x*4x*4x A formula would be (x^a)(x^b)= x^a+b x^a) / (x^b)= x^a-b
differentiation of sin x + cos x.
4x * x = 4x^2
4x
4x + -x = 3x
4X = 16X2 4X - 16X2 = 0 (1 - 4X)4X = 0 ------------------ as you see X = 0 -------- 1 - 4X = 0 - 4X = - 1 X = 1/4 ----------- So, X = 0 and X = 1/4. You check.
The differentiation of sin x plus cosx is cos (x)-sin(x).
( u(x+h) - u(x) )/ h
ANSWER: -4X2 -8X-4x (x+2)= (-4x * x) + (-4x*2)= -4X2 -8X
It is: x-4x = -3x
(4x2 - 13x - 12)/(4x+ 3) = (4x + 3)(x - 4)/(4x + 3) = (4x + 3)(x - 4)/(4x + 3) = x - 4 :)
Say you have y=x2 -4x +4 y=(x-2)(x-2) x*x=x2 x*-2=-2x -2*x=2x -2*-2=4 x2 -4x +4