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The answer depends on the metric used. The Euclidean distance is sqrt[(-3-4)2 + (5+6)2] = sqrt[72 + 112] =sqrt(49 + 121) = sqrt(170) = 13.0384 (to 6 sf).

The Minkowsky distance, on the other hand, is |-3-4| + |5+6| = 7 + 11 = 18.

There are other metrics.

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Q: What is the distance between point -3 5 and point 4 -6 in the coordinate plane?
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