The answer depends on the metric used. The Euclidean distance is sqrt[(-3-4)2 + (5+6)2] = sqrt[72 + 112] =sqrt(49 + 121) = sqrt(170) = 13.0384 (to 6 sf).
The Minkowsky distance, on the other hand, is |-3-4| + |5+6| = 7 + 11 = 18.
There are other metrics.
If you mean (4, 5) and (10, 13) then the distance is 10
To find the x-coordinate of a point on the xy-plane, you look at the horizontal distance of the point from the y-axis. The y-coordinate of a point on the xy-plane is the vertical distance of the point from the x-axis.
Point 1 = (x1, y1)Point2 = (x2, y2)d = ((x2 -x1)2 + ( y2 -x2 )2 )0.5
The answer is the x coordinate of the point.
The distance between them is the absolute value of the difference in their vertical coordinates.
If you mean (4, 5) and (10, 13) then the distance is 10
To find the x-coordinate of a point on the xy-plane, you look at the horizontal distance of the point from the y-axis. The y-coordinate of a point on the xy-plane is the vertical distance of the point from the x-axis.
If you mean points of (5, 5) and (1, 5) then the distance is 4
What is used to locate a point in a coordinate plane
Point 1 = (x1, y1)Point2 = (x2, y2)d = ((x2 -x1)2 + ( y2 -x2 )2 )0.5
The answer is the x coordinate of the point.
A translation.
The distance between them is the absolute value of the difference in their vertical coordinates.
An ordered pair of numbers on the coordinate plane denotes a point.
The centre of a coordinate plane is the point (0,0), also called the origin.
It is called a POINT!
It is simply called a point in the coordinate or Cartesian plane.