The answer depends on the metric used. The Euclidean distance is sqrt[(-3-4)2 + (5+6)2] = sqrt[72 + 112] =sqrt(49 + 121) = sqrt(170) = 13.0384 (to 6 sf).
The Minkowsky distance, on the other hand, is |-3-4| + |5+6| = 7 + 11 = 18.
There are other metrics.
If you mean (4, 5) and (10, 13) then the distance is 10
To find the x-coordinate of a point on the xy-plane, you look at the horizontal distance of the point from the y-axis. The y-coordinate of a point on the xy-plane is the vertical distance of the point from the x-axis.
Point 1 = (x1, y1)Point2 = (x2, y2)d = ((x2 -x1)2 + ( y2 -x2 )2 )0.5
The answer is the x coordinate of the point.
The distance between them is the absolute value of the difference in their vertical coordinates.
If you mean (4, 5) and (10, 13) then the distance is 10
If you mean points of (5, 5) and (1, 5) then the distance is 4
To find the x-coordinate of a point on the xy-plane, you look at the horizontal distance of the point from the y-axis. The y-coordinate of a point on the xy-plane is the vertical distance of the point from the x-axis.
What is used to locate a point in a coordinate plane
The run of a line segment is the horizontal distance between the x-coordinates of two points. To find the run, you subtract the x-coordinate of the left point from the x-coordinate of the right point. This calculation gives you the length of the base of the triangle formed by the line segment on the coordinate plane.
Point 1 = (x1, y1)Point2 = (x2, y2)d = ((x2 -x1)2 + ( y2 -x2 )2 )0.5
The answer is the x coordinate of the point.
A translation.
The distance between them is the absolute value of the difference in their vertical coordinates.
An ordered pair of numbers on the coordinate plane denotes a point.
The centre of a coordinate plane is the point (0,0), also called the origin.
It is called a POINT!