The distance from the vertex of a regular pyramid to the midpoint of an edge of the base can be found using the Pythagorean theorem. If the height of the pyramid is ( h ) and the distance from the center of the base to the midpoint of an edge is ( d ), then the distance ( D ) from the vertex to the midpoint of the edge is given by ( D = \sqrt{h^2 + d^2} ). This applies to regular pyramids where the base is a regular polygon. The specific values of ( h ) and ( d ) depend on the dimensions of the pyramid and its base.
yes it does put the mirror in the middle of the midpoint and vertex
Yes.
A triangle is not a segment joining a vertex and the midpoint of the side opposite the vertex.
Yes, the median of a triangle is from a vertex to the midpoint of the side opposite the vertex.
The distance from the vertex of a regular pyramid to the midpoint of an edge of the base can be found using the Pythagorean theorem. If the height of the pyramid is ( h ) and the distance from the center of the base to the midpoint of an edge is ( d ), then the distance ( D ) from the vertex to the midpoint of the edge is given by ( D = \sqrt{h^2 + d^2} ). This applies to regular pyramids where the base is a regular polygon. The specific values of ( h ) and ( d ) depend on the dimensions of the pyramid and its base.
A regular pyramid has a regular polygon base and a vertex over the center of the base. By:Cherrylvr :)
yes it does put the mirror in the middle of the midpoint and vertex
regular pyramid
Regular Polygon...
vertex
Yes.
Yes
A triangle is not a segment joining a vertex and the midpoint of the side opposite the vertex.
In a regular pentagon, the lines of symmetry are drawn from each vertex to the midpoint of the edge directly opposite the vertex, so there are five in all.
it is 2/3 the distance from the vertex to the midpoint on the opposite side and it is the "center of gravity"
A triangular pyramid has three lines of symmetry. Each of these lines connects a vertex of the base to the midpoint of the opposite edge on the base.