No. 760 is not evenly divisible by nine.
760 is evenly divisible by both 5 and 8
Yes, 760/4=190
yes, 95
Rule: If it is divisible by 2 and by 3Numbers are divisible by 6 if they are divisible by 3 and 2. Therefore, for example, since 18 is divisible by 3 and 2, it is also divisible by 6.The divisibility rule for 6 is, it can go into the number if 2 and 3 can also.
No. 760 is not evenly divisible by nine.
760 is evenly divisible by both 5 and 8
Yes, 760/4=190
760 is divisible by 10, so does not need to be rounded.
yes, 95
5 yes, 3 no.
Yes. For future reference, if the last two digits of any number are divisible by 4, then the number itself will always be divisible by 4.
If it is divisible by 2 and 3, it is divisible by 6.
The divisible rule for 2 is if the last digit of the number is 0,2,4,6, or 8. The divisible rule for 3 is if the last 2 digits of the number is divisible by 3,03,06,09,12,15,18,21,24,27,30,33,36,39,42,45,48,51,54,57,60,63,66,69,72,75,78,81,84,87,90,93,96, or 99.
The rule is: if a number is divisible by 5 and 17 at the same time, that number is divisible by 85
Rule: If it is divisible by 2 and by 3Numbers are divisible by 6 if they are divisible by 3 and 2. Therefore, for example, since 18 is divisible by 3 and 2, it is also divisible by 6.The divisibility rule for 6 is, it can go into the number if 2 and 3 can also.
A number is divisible by 12 if it is divisible by 3 AND it is divisible by 4. Rule 1a (Divisibility by 3): Add up all the digits of the number. Is this number divisible by 3? Rule 1b (Divisibility by 4): Is the number formed by the last two digits of the original number (the number left after deleting the hundreds, thousands, millions etc) divisible by 4? If the answer to 1a is NO, then the number is not divisible by 3 and so not divisible by 12. In this case, obviously, rule 1b is irrelevant. If the answer to 1b is NO, then the number is not divisible by 4 and so not divisible by 12. If the answer to both 1a and 1b is YES, then the number is divisible by 12.