The domain of y = x2 is [0,+infinity]
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if y = x2 + 1 Then the minimum value of y is 1, which happens at the point (0, 1). It lies in the domain of real numbers. i.e. {y | y ≥ 1, y ∈ ℝ}
x2+2x+1=y or y=x2 In this function the domain is x equals real values and the range is y equals all real values provided y is more than or equal to zero.
4
y=(√1)-x2 The domain is the set of numbers that "x" can be. In this equation "x" can be any real number. The domain for this problem would be (-inf,inf) *Inf= Infinity*
x1:y1 = x2:y2 4:-2 = x2:5 x2 = (4*5)/-2 x2 = -10