The default subnet mask for the IP address 191.249.234.191 is 255.255.255.0. This is because the address belongs to Class B, which typically uses a default subnet mask of 255.255.0.0. However, if it's using CIDR notation for subnetting, it may also commonly be configured with a mask of 255.255.255.0 for more specific network segmentation.
Yes, the IP subnet 88.33.0.0 with a mask of 255.255.128.0 overlaps with the subnet 88.33.89.0 with the same mask. The subnet mask 255.255.128.0 indicates that the first 17 bits are the network part, meaning subnets can range from 88.33.0.0 to 88.33.127.255. Since 88.33.89.0 falls within this range, the two subnets indeed overlap.
Subnet Mask: Subnet mask is a 32 bits value which differentiate the host portion & network portion of an IP address. Where network portion is designate by the 1's & host portion 0's. Wild card Mask: Wild card mask defines which IP addresses are allowed & which are blocked. Where 0's defines the accurate match where non zero value defines any value on the corresponding octete.
This is not a valid IP address - a valid IP address has 4 bytes. Also, you can't guess the subnet mask from looking only at the IP address; there are usually several options.
No, 255.247.0.0 is not a valid subnet mask. A valid subnet mask must have contiguous bits set to 1 followed by contiguous bits set to 0, which means that after the 1s, all subsequent bits should be 0. The binary representation of 255.247.0.0 does not adhere to this rule, as it has non-contiguous 1s and 0s.
12
dotted decimal notation
"Subnet mask" is is a computer term related to IP networks. Since you haven't given your example, the question cannot be answered. Further information can be found by searching for 'subnet mask' in Wikipedia.
Subnet mask
255.255.248.0
True
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Given a Class C network: 200.1.1.0 We want 5 subnets, each with 30 hosts on it. How many bits to borrow ? How many bits to leave? What is the subnet mask? ( in dot notation and in CIDR notation)
Example IP address of 192.168.1.123 with a subnet mask of 255.255.255.0
The term "slash notation" refers to the way a processor reads an IP address. The "Watchguard" website gives a table showing the most common network masks and their equivalent in slash notation.
This isn't a valid CIDR address, so I assume it is: 192.168.1.162/7 That would yield a subnet mask of 255.255.255.254
It does not require a subnet mask.