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Q: What is the dotted decimal notation for a 23 bit subnet mask?
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What is difference between subnet-mask and wildcard mask?

Subnet Mask: Subnet mask is a 32 bits value which differentiate the host portion & network portion of an IP address. Where network portion is designate by the 1's & host portion 0's. Wild card Mask: Wild card mask defines which IP addresses are allowed & which are blocked. Where 0's defines the accurate match where non zero value defines any value on the corresponding octete.


What is the subnet mask for 10 0 10 1 17?

This is not a valid IP address - a valid IP address has 4 bytes. Also, you can't guess the subnet mask from looking only at the IP address; there are usually several options.


What is the second subnet of 172.16.0.0?

172.16.0.0/16 gives you 65534 possible hosts within 1 subnet. By binary math, you would need to increase the subnet mask to divide the network into subnets. Think of the additional subnet mask bits as a binary value. With 0 extra bits in the masks, you have 1 subnet. With 1 bit, you have 2. With 2 bits, you have 4. With 3 bits, you have 8. With 4 bits, you have 16. We need 8, so we should add 3 bits to the subnet mask. This would be a base CIDR of 172.16.0.0/19. Since there are 256 possibilities in the 3rd octet (Based on Class B network), divide by 8. The resultant number is the increment value for each network address. 256 / 8 = 32. Therefore, your networks would be: 172.16.0.0/19 172.16.32.0/19 172.16.64.0/19 172.16.96.0/19 172.16.128.0/19 172.16.160.0/19 172.16.192.0/19 172.16.224.0/19 With maximum (65536 / 8 - 2) 8190 hosts per subnet. Additional: Since we have 19 network bits, there are 13 bits remaining for hosts (total, as always 32). An all 0 string of host bits would leave you with your base network number ex> 172.16.0.0/19 , host with all 0's 10101100.00010000.00000000.00000000 The resultant would be 172.16.0.0, which is your network address. Conversely, having a host with all 1's: 10101100.00010000.00011111.11111111 This would result in 172.16.31.255, which is the broadcast address for the first subnet. These aren't usable as assignable addresses, but are used for network and broadcast purposes. Using all of the 3 borrowed bits in a 111 situation gives you a resultant of 172.16.224.0/19, which is a legitimate network address. Network bits in this case carry over from the /16, and are simply added on. An IP address of 172.16.255.255 would be the broadcast address for the final subnet. ex> 10101100.00010000.11111111.11111111 If you were doing a class A network, this wouldn't be as applicable. If all 3 of the first bits of a network address are 1, this puts your IP into a class D (224.0.0.0/4) subnet which is reserved for multicasting. This is only applicable to the first bits of the network address (starting from the very beginning). Hope this helped at least a little.


What are some of the companies that produce a 3M Mask?

The 3M Company used to produce the 3M Mask. However, they sold the liquid mask name to the Trimex Company who now produces the 3M Mask and calls it Trimex Window Mask.


Where can you get a aces and eights mask?

My name is joshua broome aces and eights i like to have one vest and mask too