Diameter = 11.14 inches (approx) ~ Circumference can be found by pi * diameter.
1 foot = 12 inch 35 feet = 420 inch
A = 962.11 units2
Circumference = 2*pi*rr = diameter/2 = 70/2 = 35 yards2*pi(35 yards)= 220 yards in circumference===================
Radius: 35/2 = 17.5cm
Noop. A 380 is about 35/100th of an inch (diameter of bullet), or 9mm A 32 is about 32/100th of an inch. This is 8.1mm
11 is a good approximation of the diameter. If the circumference is 35, the actual diameter is about 11.14 (35/3.1416).
If 35 is the radius, then its 70.
The diameter of a circle when the circumference is 35 cm is: 11.14 cm (circumference divided by Pi = diameter).
The circumference of a circle that has a diameter of 35 inches is 109.96 inches.
One can make a pistol much larger than it needs to be, maybe even having an extra-long barrel would make a pistol larger, technically. I'll assume you mean the barrel diameter. Although it would seem that a .380 and .38 would have the same barrel diameter, namely, 38/100th of an inch, that is not usually very accurate. The .380 ACP has an actual barrel diameter of about .35 caliber, or 35/100th of an inch. The .38 Special has a barrel diameter of .357 caliber, or 35.7/100th of an inch. So the .38 Special has an ever so slightly larger diameter.
Perhaps 35 inch squared!
34A is one inch larger diameter around the bust then around the chest (34 around ribcage, 35 around bust).
9mm is roughly .35 caliber, .32 caliber is slightly smaller, 3 hundredths of an inch smaller, in diameter.
Total 35 :- 22-SP,7-BJP,3-BSP,3-CONGRESS.
Diameter = 11.14 inches (approx) ~ Circumference can be found by pi * diameter.
I think you mean .32 caliber, not mm. It means that the gun fires a bullet that is about 32/100ths of an inch in diameter. A 9mm fires a bullet 9mm in diameter- or about .35 inches in diameter. A 32 mm bullet would be about the size of big (D cell) flashlight battery!