I believe you are talking about subsets. The empty set (set with no elements) is a subset of any set, including of the empty set. ("If an object is an element of set A, then it is also an element of set B." Since no element is an element of set A, the statement is vacuously true.)
No. An empty set is a subset of every set but it is not an element of every set.
No.
An item in a set is called an element.An item in a set is called an element.
It is a member of a set.
an empty set does not have any element
I believe you are talking about subsets. The empty set (set with no elements) is a subset of any set, including of the empty set. ("If an object is an element of set A, then it is also an element of set B." Since no element is an element of set A, the statement is vacuously true.)
No. An empty set is a subset of every set but it is not an element of every set.
The empty element is a subset of any set--the empty set is even a subset of itself. But it is not an element of every set; in particular, the empty set cannot be an element of itself because the empty set has no elements.
No, but it is a subset of every set.It is an element of the power set of every set.
I will provide a name of an element from the set if you provide the set for me. Please specify the set you are referring to.
No.
An item in a set is called an element.An item in a set is called an element.
A is a subset of the larger set. This means that every element in set A is also an element in the larger set.
It is a member of a set.
Elements can be an element of a set. Lets say you have a set of numbers like A{2,3,5,8,45,86,9,1} B{2,7,0,100} all those numbers are called elements of that set 2 is an element of set A and B 100 is an element of set B 45 is an element of set A
If every element of the first set is paired with exactly one element of the second set, it is called an injective (or one-to-one) function.An example of such a relation is below.Let f(x) and x be the set R (the set of all real numbers)f(x)= x3, clearly this maps every element of the first set, x, to one and only one element of the second set, f(x), even though every element of the second set is not mapped to.