Q: What is the equation for a circle with a center of 0 2 and a radius of 11?

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Centre = (0,0), the origin; radius = 11

the general equation of the circle is (x-a)^2+(y-b)^2=r^2 where (a,b) is the center of the circle. r is the radius of the circle substituting the given values, (x+4)^2+(y-3)^2=6^2 x^2+y^2+8x-6y+16+9=36 x^2+y^2+8x-6y=11

5.5 is the radius.

the radius is half the diameter. radius is half of 11. Which is 5.5.

A circle with a radius of 11 inches has an area of 380.13 square inches.

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Centre = (0,0), the origin; radius = 11

The equation is: (x -0)^2 +(y -2)^2 = 121

It is (x - 1)^2 + (y - 1)^2 = 5^2

the general equation of the circle is (x-a)^2+(y-b)^2=r^2 where (a,b) is the center of the circle. r is the radius of the circle substituting the given values, (x+4)^2+(y-3)^2=6^2 x^2+y^2+8x-6y+16+9=36 x^2+y^2+8x-6y=11

If you mean (-3, 5) and (5, 11) then using the distance formula the radius of the circle is 10 units

5.5 is the radius.

the radius is half the diameter. radius is half of 11. Which is 5.5.

The circumference of a circle with a radius of 11 is: 69.12

A circle with a radius of 11 inches has an area of 380.13 square inches.

The radius is 11.

If this is the equation of a circle, the answer is 11, except that there needs to be a plus sigb between the x2 and the y2

A circle with a radius of 11m has an area of ~380.13 m2