x2/242-y2/62=1
you
y2/52 - x2/72 = 1
x^2/11^2 - y^2/5^2
x2/172 - y2/b2 = 1 for some constant b.
True
you
x2/242-y2/62=1
y2/52 - x2/72 = 1
x2/172 - y2/b2 = 1 for some constant b.
x^2/11^2 - y^2/5^2
y^2/15^2 - x^2/6^2 = 1
true
True
x2/132-y2/152=1
difference between
true
The standard form of the equation of a hyperbola with center at the origin isx2/a2 - y2/b2 = 1 where the transverse axis lies on the x-axis,ory2/a2 - x2/b2 = 1 where the transverse axis lies on the y-axis.The vertices are a units from the center and the foci are c units from the center.For both equations, b2 = c2 - a2. Equivalently, c2 = a2 + b2.Since we know the length of the transverse axis (the distance between the vertices), we can find the value of a (because the center, the origin, lies midway between the vertices and foci).Suppose that the transverse axis of our hyperbola lies on the x-axis.Then, |a| = 24/2 = 12So the equation becomes x2/144 - y2/b2 = 1.To find b we need to know what c is.