answersLogoWhite

0


Best Answer

The voltage of a winding that is connected in star is 1 over the square root of three, 1 / 1.732, or 0.5774, of the voltage if that winding were connected in delta. This results in a star power of 1/3, or 0.3333, of the delta power.

Similarly, if you know the winding current in delta, you can calculate the star current by multiplying by 1.732.

This all presumes that the neutral point of the star is symmetrically centered in the middle of the phase triangle.

User Avatar

Aditya Jaskolski

Lvl 9
2y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: What is the equation of (3-1)?
Write your answer...
Submit
Still have questions?
magnify glass
imp