yes
area of the rectangle..
3x9 ones = 27
The equation for the area of the rectangle is A = Y2 + 4 Y. A = L * W = (Y + 4) (Y)
(a(rectangle))(.25)+(a(rectangle))(.25)=(a(rectangle))(.5)I REALLY hope you can read algebraic expressions, 'cause if you can't....the above equation will make no sense to you.
yes
27 square feet
area of the rectangle..
3x9 ones = 27
Same as a rectangle. It is, after all, a type of rectangle (lenght >< width)
27
you must know the length of the rectangle as well in order to fill in the equation A=lengthxWidth
A = L*B where L is the length of a rectangle, measured in centimetres (say); B is the breadth of the rectangle in cm and A is the area of the rectangle in cm2
The equation for the area of the rectangle is A = Y2 + 4 Y. A = L * W = (Y + 4) (Y)
2.5
The equation for a rectangle is h(height) x w(width) = area . By manipulating the equation we can show that width=area/length. So 132/12=11. This means the width of the rectangle is 11.
Assign the rectangle a width 'x'. From the data in the problem the height is then '2x+1'. Multiplying the two together gives the area of the rectangle, which we know to be 45. In equation for this is: x(2x+1) = 45 or 2x^2 + x = 45. The roots of this equation can then be found either through the quadratic equation or a calculator solver (I used the solver because I'm lazy) and the answers are x = -5 and x= 4.5. The rectangle has a width of 4.5 and a height of 10.