Q: What is the equation of a line that is parallel to 4y -12x 8 and that has a y-intercept of -4?

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y = - 4x - 4

If the equation is y=12x, the slope is 12

y=x2-12x+7

2y-12x=-6 is the equation of a line. It has infinite number of solutions which are all the points one the line. We can rewrite the equation as 2y=12x-6 and then divide both sides by 2.This gives us y=6x-3. From this we know the equation describes a line with y intercept -2 and slope 6.

If you mean: y = -3x, then the line y = -3x+2 will be parallel to it because they both have the same slope.

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y = - 4x - 4

So the given line is y=12x-8 and the given point is x=2 y=15? 15=12*2+m m=-9 y=12x-9

If the equation is y=12x, the slope is 12

If you mean y = 12x then the slope of the line is 12

12

12

If you mean y = 12x then the slope of the line is 12

y=x2-12x+7

2y-12x=-6 is the equation of a line. It has infinite number of solutions which are all the points one the line. We can rewrite the equation as 2y=12x-6 and then divide both sides by 2.This gives us y=6x-3. From this we know the equation describes a line with y intercept -2 and slope 6.

If you mean: y = 12x-23 then the slope is 12 and the y intercept is -23

If you mean: y = -3x, then the line y = -3x+2 will be parallel to it because they both have the same slope.

It is: y = 12x+4