Point: (2, 17)
Slope: 7
Equation: y = 2x+13
That will depend on the value of the slope which has not been given.
To write the point-slope equation of a line that passes through the point (5, 5), you need a slope (m) as well. The point-slope form is given by the equation ( y - y_1 = m(x - x_1) ). If the slope is not provided, you can express the equation generically as ( y - 5 = m(x - 5) ), where ( m ) is the slope of the line. If you have a specific slope, you can substitute it into the equation.
You can have infinitely many lines through one specific point, each with a different equation. If you want to have a general equation for ANY line that goes through that point, use the point-slope equation for a line, and use a variable for the slope.
When it is a line through the origin.
Given a point P = (a,b) and slope m, the equation of a line through P with slope m is (y-b) = m(x-a)
That will depend on the value of the slope which has not been given.
To write the point-slope equation of a line that passes through the point (5, 5), you need a slope (m) as well. The point-slope form is given by the equation ( y - y_1 = m(x - x_1) ). If the slope is not provided, you can express the equation generically as ( y - 5 = m(x - 5) ), where ( m ) is the slope of the line. If you have a specific slope, you can substitute it into the equation.
You can have infinitely many lines through one specific point, each with a different equation. If you want to have a general equation for ANY line that goes through that point, use the point-slope equation for a line, and use a variable for the slope.
If you mean a slope of -12 through the point (5, 3) the equation is y = -12x+63
If you mean a slope of -10 through the point (1, 4) then the equation is y = -10x+14
When it is a line through the origin.
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
Given a point P = (a,b) and slope m, the equation of a line through P with slope m is (y-b) = m(x-a)
If you mean: slope of -13 and point of (5, 7) then the equation is y = -13x+72
If you mean slope of -10 and point of (1, 4) then the equation is y = -10x+14
The point-slope form of a line's equation is given by (y - y_1 = m(x - x_1)), where (m) is the slope and ((x_1, y_1)) is a point on the line. Given the slope (m = -5) and the point ((1, -1)), the equation in point-slope form is (y + 1 = -5(x - 1)).
It is: y = -10x+14