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y-3 = -1/2(x-0)

y = -1/2x+3

Q: What is the equation of the line that passes through the point 0 and 3 and is perpendicular to the line y equals 2x plus 3?

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Perpendicular slope: -2/5 Perpendicular equation: y--4 = -2/5(x-3) => 5y--20 = -2x-3 => 5y = -2x-14 Perpendicular equation in its general form: 2x+5y+14 = 0

If -14 is the y intercept then it is: y = -1/13x -14

If you mean 7 = 7x-3 then the perpendicular slope is -1/7 and the equation is y = -1/7x

Perpendicular slope: -1/4 Perpendicular equation: y-0 = -1/4(x-3) => y = -0.25x+3

2-3

Related questions

Slope: -2 Equation: y--1 = -2(x-3) => y = -2x+5

It works out in its general form as: 3x-4y-6 = 0

Perpendicular slope: -2/5 Perpendicular equation: y--4 = -2/5(x-3) => 5y--20 = -2x-3 => 5y = -2x-14 Perpendicular equation in its general form: 2x+5y+14 = 0

If -14 is the y intercept then it is: y = -1/13x -14

If you mean 7 = 7x-3 then the perpendicular slope is -1/7 and the equation is y = -1/7x

That depends on the equation that it is perpendicular too which has not been given but both equations will meet each other at right angles.

The line "x = 6" will be perpendicular to any line "y = C", where C is any constant. That means that the line which is perpendicular to "x=6" and passes through [-4, 5] will be "y = 5"

Perpendicular slope: -1/4 Perpendicular equation: y-0 = -1/4(x-3) => y = -0.25x+3

2-3

Find an equati find an equation for the line perpendicular to the line 8x - 8 y equals negative 2 having the same Y intercept as -6x + 2 y equals negative 8

Known equation: 5x -2y=3 => y=5/2x -1.5 Slope of equation: 5/2 Perpendicular slope: -2/5 Perpendicular equation: y--4=-2/5(x-3) => 5y--20=-2x+6 => 5y=-2x-14 Therefore the perpendicular in its general form is: 2x+5y+14 = 0

General formula