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What is the equation whose solutions are x equals 2 over 3 and x equals 5 over 7 showing work?
x-2/3 = 0
x - 5/7 = 0
(x-2/3)(x-5/7) = 0
x^2 -2/3(x) -5/7(x) + 10/21 = 0
x^2 -14/21(x) - 15/21(x) +10/21 = 0
x^2 -29/21(x) +10/21 = 0
Another Answer:-
If: x = 2/3 and x = 5/7
Then: (3x-2)(7x-5) = 0
Multiplying out the brackets: 21x2-29x+10 = 0 which is the equation.
Check using the quadratic equation formula: x = 2/3 and x = 5/7
What else can I help you with?
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