Points: (11, 0) and (0, 13)
Slope: (0-13)/(11-0) = -13/11
Equation: y-0 = -13/11(x-11) => 11y = -13x+143
Equation: y-13 = -13/11(x-0) => 11y = -13x+143
Points: (2, 3) and (11, 13) Slope: 10/9 Equation: 9y = 10x+7
The simplest way is to change the subject of the formula so that it is in the form y = mx + c. There are alternatives, but a lot more work. Differentiate the equation equal to x, and solve for dy/dx (that is the slope). Substitute x = 0 in the original equation and solve for y (that is the intercept).
Not enough information has been given because in order to work out a straight line equation the slope and coordinates of (x, y) must be given
The slope intercept form is expressed as y = mx + c, where m is the slope and c is the y intercept.If you had a slope intercept linear equation such as y = -1/3x + 5Then this could be presented in a non standard form 3y = 15 - xEach format has its benefits and these will become apparent as your graph/coordinate work develops.
The equation in slope-intercept form of a line that is parallel to a given line can be written as y = mx + b, where m is the slope of the given line and b is the y-intercept. However, since the slope is not provided in the question, the equation cannot be determined.
You need a pair of coordinates to work out the slope-intercept equation.
Points: (2, 3) and (11, 13) Slope: 10/9 Equation: 9y = 10x+7
Substitute the value x = 0 in the equation of the line. Here you get y = 0-4 = -4. So, the y-intercept is -4 ie the line intercepts the -axis at (0,-4).
The simplest way is to change the subject of the formula so that it is in the form y = mx + c. There are alternatives, but a lot more work. Differentiate the equation equal to x, and solve for dy/dx (that is the slope). Substitute x = 0 in the original equation and solve for y (that is the intercept).
Not enough information has been given because in order to work out a straight line equation the slope and coordinates of (x, y) must be given
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The slope intercept form is expressed as y = mx + c, where m is the slope and c is the y intercept.If you had a slope intercept linear equation such as y = -1/3x + 5Then this could be presented in a non standard form 3y = 15 - xEach format has its benefits and these will become apparent as your graph/coordinate work develops.
The equation in slope-intercept form of a line that is parallel to a given line can be written as y = mx + b, where m is the slope of the given line and b is the y-intercept. However, since the slope is not provided in the question, the equation cannot be determined.
Not enough information has been given because in order to work out a straight line equation the slope and coordinates of (x, y) must be given
Points: (7, 0) and (0, 11) Slope: 0-11/7-0 = -11/7 Equation: y-0 = -11/7(x-7) => 7y = -11x+77 Equation: y-11 = -11/7(x-0) => 7y = -11x+77
that's not possible to work out from that, firstly you need y and x and, secondly, as the equation of a line is an equation, you need something to equal something else, e.g y=mx+c
It is a bit difficult to be sure about the answer because the rubbish browser that we all have to work with strip out mathematical symbols (here, the equals sign). Assuming the equation which you used was 2x + 5y = 20, the slope is -0.4 and the intercept is 4.