It is a linear equation in x. It has a solution, which is x = -5
If 3x = x + 10 then 2x = 10 and x = 5
x2 + 3x - 10 = (x + 5)(x - 2) ⇒ x = -5 or 2
Rearrange the second equation as x = 10+y and then substitute it into the first equation which will create a quadratic equation in the form of: 2y2+30y+100 = 0 and when solved y = -10 or y = -5 Therefore the solutions are: x = 0, y = -10 and x = 5, y = -5
It's a simple first-degree equation in 'x'.Its solution is [ x = 5 ].
It is a linear equation in x. It has a solution, which is x = -5
If 3x = x + 10 then 2x = 10 and x = 5
(5, 0)
x2 + 3x - 10 = (x + 5)(x - 2) ⇒ x = -5 or 2
Rearrange the second equation as x = 10+y and then substitute it into the first equation which will create a quadratic equation in the form of: 2y2+30y+100 = 0 and when solved y = -10 or y = -5 Therefore the solutions are: x = 0, y = -10 and x = 5, y = -5
2x + 5 = 25 2x = 20x = 10
It is a linear equation in x. The equation has the solution x = 0.
It's a simple first-degree equation in 'x'.Its solution is [ x = 5 ].
In order to solve for X, or find out what X equals, you need to get the X alone on one side of the equation. In this case, first you subtract the Y so that the equation becomes 5x=10-y. Then you divide both sides by 5. Now the equation is X=(10-y)/5 (or X equals the quantity of 10-y over 5).
5x + 2 = x + 12 5x - x = 12 - 2 4x = 10 x = 10/4 x = 5/2 or 2.5
It could be y = -x+5
6x + 10 > x - 5