4 hr and 21 min
10:05 --> 10 * 60 min + 5 min = 605 min 08:20 --> 8 * 60 min + 20 min = 500 min 605 min - 500 min = 105 min (= 1 3/4 hr)
60 min = 1 hr ⇒ 330 min = 330 ÷ 60 hr = 51/2 hr = 5.5 hr
3 hr = 180 min. 200 min. is greater.
There are 60 min in an hr ... SO60 min x 2½ min/hr = 150 min.
4 hr 30 min ÷ 3 = 1 hr 30 min Either work directly, remembering 1 hr = 60 mins: 4 hr ÷ 3 = 1 hr remainder 1 hr 1 hr + 30 min = 60 min + 30 min = 90 min 90 min ÷ 3 = 30 min ⇒ 1 hr 30 min Or, convert to minutes, do the calculation and convert back: 1 hr = 60 min ⇒ 4 hr 30 min = 4 x 60 min + 30 min = 270 min 270 min ÷ 3 = 90 min 60 min = 1 hr ⇒ 90 min = 90 ÷ 60 hr = 1 hr 30 min Alternatively working in hours: 30 min = 30 ÷ 60 hr = 0.5 hr ⇒ 4 hr 30 min = 4 hr + 0.5 hr = 4.5 hr 4.5 hr ÷ 3 = 1.5 hr = 1 hr + 0.5 hr = 1 hr + 0.5 x 60 min = 1 hr 30 min
Convert 30 mcg/k/min into have on hand 120mg/100ml. childs weight 55lb
2310 sec * 1 min/60 sec * 1 hr/60 min is 0.642 hr.
(mcf/day*1000)/24=scf/hr (scf/hr)/24=scf/min
4 hr and 21 min
10:05 --> 10 * 60 min + 5 min = 605 min 08:20 --> 8 * 60 min + 20 min = 500 min 605 min - 500 min = 105 min (= 1 3/4 hr)
21763874 min ÷ (60 min/hr) ÷ (24 hr/day) = 21763874 min * 1 hr / 60 min * 1 day / 24 hr ≈ 15,113.8 days
60 min = 1 hr ⇒ 330 min = 330 ÷ 60 hr = 51/2 hr = 5.5 hr
3 hr = 180 min. 200 min. is greater.
main() { int sec=00,min=00,hr=00; printf("Enter time in seconds"); scanf("%d",&sec); if (sec<60) printf("%d :%d : %d",hr,min,sec); else if(sec>=60) min=int(sec/60); sec=int(sec%60); printf("%d: %d : %d",hr,min,sec); else if (sec>=3600) min=int(sec/60); sec=int(sec/60) hr=int(min/60); printf("%d : %d : %d",hr,sec,min); }
There are 60 min in an hr ... SO60 min x 2½ min/hr = 150 min.
gal/day x day/24 hrs x hr/60 min = gal/day x day/1440 min = gal/min ie divide by 1440