238 = (2 x 10^2) + (3 x 10^1) + (8 x 10^0)
Expanded Form of a Decimal Number:88.29 = 80 + 8 + 0.2 + 0.09Expanded Exponential Notation: Expanded Notation of 88.29 = (8 x 101) + (8 x 100) . (2/101) + (9/102)
To which base? To base e (natural logarithms) loge 589 ~= 6.378 To base 10 (common logarithms) log10 589 ~= 2.77 To base 2 (a base I quite like) log2 589 ~= 9.202
Exponential notation for 400 would be 4 * 10 ^ 2.
What is the exponential notation for 0.000981
multiply all the coefficients out. imagine 2 to the 5th power. this is 2x2x2x2x2.
0.384 in expanded notation using exponential notation is: (0 x 10^0) + (3/10^1) + (8/10^2) + (4/10^3)
5 × 103+8 × 102+3 × 101+2 × 100
4 × 104+5 × 103+2 × 102+7 × 101+0 × 100
It is: 604/2 = 302
238 = (2 x 10^2) + (3 x 10^1) + (8 x 10^0)
62.85 = (6 x 101) + (2 x 100) + (8/101) + (5/102).
The positive integer factors of 604 are: 1, 2, 4, 151, 302, 604
Expanded Form of a Decimal Number:88.29 = 80 + 8 + 0.2 + 0.09Expanded Exponential Notation: Expanded Notation of 88.29 = (8 x 101) + (8 x 100) . (2/101) + (9/102)
302 times 2 gives you 604.
Expanded Notation of 126 with exponents = (1 x 102) + (2 x 101) + (6 x 100).
Expanded Notation of 2155 = (2 x 1000) + (1 x 100) + (5 x 10) + (5 x 1).Expanded Exponential Notation of 2155 = (2 x 103) + (1 x 102) + (5 x 101) + (5 x 100).