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Experimental probability depends on each trial. It is not known until you conduct the trial. You are probably talking about theoretical probability in the question.

The solve this problem, simplify it...

The probability of rolling a 1 or a 2 in a standard six sided die is 1 in 3, or about 0.3333. Remember this, because I'm going to change the problem.

Think about throwing a coin. What is the probability of throwing 39 heads in 100 coin tosses? Its the same problem, and I'll show this at the end.

The probability of throwing a head is 1 in 2, or 0.5. The probability of throwing 39 heads in 100 coin tosses is more difficult.

The real question is, what is the number of combinations of 100 things taken 39 at a time? Sound familiar? It better. Each of those 39 events corresponds to a head, and the 100 things is the number of coin tosses. The answer is that the number of combinations of 100 things taken 39 at a time is 100! / (39! (100-39)!), or about 9.0139 x 1027.

Since probability is the number of permutations of the desired outcome divided by the number of permutations of the possible outcome, simply divide the above number by 100!, or 9.3326 x 10157, getting about 9.6585 x 10-131.

Now, back to the original problem. We were talking about a six-sided die, and wanting a sample space of 6, but coins have a a sample space of 2. Reconsider and you find that the actual sample space is 3, because we want a 1 or a 2, so multiply 9.6585 x 10-131 by 2/3 to get 6.439 x 10-131. That is the probability of rolling a 1 or a 2 exactly 39 times in 100 rolls.

From Rafaelrz:

You have two possible events in a single throw of the die: A, die comes out 1 or 2; B, die comes out 3,4,5,or 6.

Probability of events are; P(A) is 1/3, P(B) is 2/3.

If you want 39 'A' events in a trial of 100 throws, the number of ways this events

can happen ( in which number of throw they appear ) is given by the number of

combinations above calculated nCr (n is 100, r is 39) with the result of about

9.01392403 x 1027.

Then, the probability of getting 39 'A' events in a trial of 100 throws is:

100C39 x [P(A)]39 x [P(B)]61 equal to 9.01392403 x 1027 x (1/3)39 x (2/3)61

equal to 0.040329065 ( Theoretical probability )

Q: What is the experimental probability of rolling one die 100 times and getting a 1 or a 2 39 times?

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To find the experimental probability of rolling a 2 on a number cube (a 6-sided die) rolled 50 times, you need to follow these steps: **Count the number of times a 2 is rolled**: After rolling the die 50 times, count how many times the result was a 2. Let's call this number ( x ). **Calculate the experimental probability**: The experimental probability is the ratio of the number of favorable outcomes (rolling a 2) to the total number of trials (50 rolls). This can be calculated as: [ \text{Experimental Probability} = \frac{x}{50} ] Where ( x ) is the number of times a 2 was rolled. For example, if you rolled a 2 exactly 8 times out of 50, the experimental probability would be: [ \frac{8}{50} = 0.16 ] So, the experimental probability of rolling a 2 would be 0.16 or 16%. You would need to know the actual count of how many times a 2 was rolled to calculate the exact experimental probability.

It is 60/100 = 0.6

1/2

1/6

The probability is approx 0.1608

Related questions

The probability of rolling at least one 2 when rolling a die 12 times is about 0.8878. Simply raise the probability of not rolling a 2 (5 in 6, or about 0.8333) to the 12th power, getting about 0.1122, and subtract from 1.

It is 60/100 = 0.6

1/2

The probability is: 1/6 times 1/6 = 1/36

1/6

The probability is approx 0.1608

To find the experimental probability of an event you carry out an experiment or trial a very large number of times. The experimental probability is the proportion of these in which the event occurs.

Theoretical probability is the probability of something occurring when the math is done out on paper or 'in theory' such as the chance of rolling a six sided dice and getting a 2 is 1/6. Experimental probability is what actually occurs during an experiment trying to determine the probability of something. If a six sided dice is rolled ten times and the results are as follows 5,2,6,2,5,3,1,4,6,1 then the probability of rolling a 2 is 1/3. The law of large numbers states the more a probability experiment is preformed the closer to the theoretical probability the results will be.

The probability of getting a sum of 2 at least once is 0.8155

The difference between experimental probability and theoretical probability is that experimental probability is the probability determined in practice. Theoretical probability is the probability that should happen. For example, the theoretical probability of getting any single number on a number cube is one sixth. But maybe you roll it twice and get a four both times. That would be an example of experimental probability.

Probability is a number between 0 and 1. The probability of an event cannot be 12.

One way of finding the probability is to carry out an experiment repeatedly. Then the estimated experimental probability is the proportion of the total number of repeated trials in which the desired outcome occurs.Suppose, for example you have a loaded die and want to find the probability of rolling a six. You roll it again and again keeping a count of the total number of rolls (n) and the number of rolls which resulted in a six, x. The estimated experimental probability of rolling a six is x/n.