x^2 + 7x + 10
Since the 'x^2' term has a coefficient of '1' ( no number), then we look at the constant (10).
We need two numbers that multiply to '10' and add to '7'.
They are '5' & '2'
Hence setting up brackets
( x 5 )(x 2)
We note in the quadratic expression all the terms are positive(+) so plus(+) sign go in .
( x + 5)( x + 2)
Factored
Done!!!!
10 - 20x = (10) (1 - 2x)
The expression ( t^2 + 3t - 10 ) is a quadratic polynomial in terms of ( t ). It can be analyzed or factored, if possible, to find its roots or vertex. To factor it, you would look for two numbers that multiply to -10 and add to 3, which are 5 and -2. Thus, it can be factored as ( (t + 5)(t - 2) ).
(2x+10)(x+4)
12x2-23x+10 = (3x-2)(4x-5) when factored
In the expression '15b + 23b + 10', the coefficients are 15, 23, and 10.If you simplify the expression to '38b + 10", then the coefficients are 38 and 10.
10(u + 30)
The expression cannot be factored.
It is an algebraic expression in the form of: 8x+10
If you mean 4y+10 then it is 2(2y+5) when factored
The expression is: 6x-10 which can be factored to 2(3x-5)
10 - 20x = (10) (1 - 2x)
a2+3a-10 = (a-2)(a+5) when factored
(2x+10)(x+4)
5/ 2 -4/ 5 plus 2 expression can be written in simple form as 37/10.
the form of an expression compossed of products of factors, rather than sums or differences of terms. the expressions x(x-2) and (x+3)(x+4) are in factored form. y=(x-2)(x+5), or factored form, is an equation that describes a parabola. Once factored, using a FOIL method, it becomes standard form. y=(x-2)(x+5) y=x^2+5x-2x-10 y=x^2+3x-10
(3r + 8)(11r - 10)
The correct factorization of 5 x plus 2 -3x x plus 2 is 2x+4.