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x^2 - 6x + 48

The factors of 48 are 1,48 : 2,24 : 4.12 : 8,6 ; 3,16

None of these numbers has a difference of '6' .

So resort to the Quadratic Equation.

x = - b +/- sqrt[b^2 - 4ac]}/ 2a

Substituting

x = { - -6 +/- sqrt[(-6)^2 - 4(1)(48)]} / 2(1)

x = { 6 +/- sqrt[36 - 192]} / 2

x = { 6 +/- sqrt[-156]} 2

This does not have any REAL roots/factors, because you cannot take the square root of a negative number.

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lenpollock

Lvl 16
1y ago

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Wiki User

13y ago

It has no real solutions. The complex factorization is (x-(3+sqrt(39)i))(x-(3-sqrt(39)i)

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Q: What is the expression in factored form x2-6x plus 48?
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