13 * x * y * y
No.
The GCF is 15x^2y^2
y2 - 36 does not have a value unless we know what y is. We can, however, factor this expression: it factors to (y + 6)(y - 6).
14x = 7y+28 -7y = -14x+28 Divide all terms by -7 to find the value of y: y = 2x-4 which is now in slope intercept form
13 * x * y * y
No.
The GCF is 15x^2y^2
y2 - 36 does not have a value unless we know what y is. We can, however, factor this expression: it factors to (y + 6)(y - 6).
If you mean: y = 14x+2 then the slope is 14 and the y intercept is 2
Since y=14x is a perfect linear relation, the correlation would be 1.
14x = 7y+28 -7y = -14x+28 Divide all terms by -7 to find the value of y: y = 2x-4 which is now in slope intercept form
y4
There can be no answer without values for x and y.
You can answer this by the method of substitution, which means that you find what one variable equals and you substitute it into the second equation to find the other variable.14x-2y=78; solve for y-2y=78-14x; subtract 14x on both sidesy=-39+7x; divide both sides by -2y=7x-39Substitute 7x-39 for y in the second equation.2x-2(7x-39)=6; solve for x2x-14x+78=6; distribute the -2-12x+78=6-12x=-72; subtract 78 on both sidesx=6; divide both sides by -12Now go back to the first equation and for x, substitute 6. You can either substitute in 14x-2y=78 or the y=7x-39, but it's easier where you already have y isolated.y=7(6)-39y=42-39y=3You got that x=6 and that y=3; therefore, the ordered pair is (6,3).
It is: (x-y)4
x^2+y^2=25 and y=x-7. This question is interesting since the first equation is a circle of radius 5 and the second is a line with slope 1 and y intercept -7. The solution will be the where the line intersects the circle. If you plug in y=x-7 into the equation of the circle and solve for x you can find he answer. Plugging in x-7 for y we have 2x^2-14x+49=25 or 2x^2-14x+24=0 which we can factor as 2(x-3)(x-4) So the solutions are x=3 and x=4. If you plug that into the equation of the line you find y=4-7, so y=-3 and y=3-7 so y=-4. The solutions are (4,-3) and (3,-4). This means the line intersects the circle in two points.