2(n2+3n-54)
2(n+9)(n-6)
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If the question is, "What is the solution to 2n2 + 6n - 108 = 0 ?"The equation can be factored : 2n2 + 6n - 108 = (2n - 12)(n + 9) = 0If 2n -12 = 0 then n = 6If n + 9 = 0 then n = -9The roots of this equation are n = 6 and n = -9.
factor by grouping 7m(m-2)+6n(2-m)
(m - 3n)(m + 3n - 2)
(m - 3n)(m + 3n - 2)
3(3n - 1)(n + 1)