Q: What is the factorization of the trinomial- x3 plus 13x2 plus 42x?

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x3 + 13x2 + 42x = x(x2 + 13x + 42) = x(x2 + 6x + 7x + 42) = x[x(x + 6) + 7(x + 6)] = x(x + 7)(x + 6)

5x - 42x + 5 = - 37 x +5

42x+35x-35x=42x it's leave 85 so it's change into a negative 42x-85 is the answer

-1/19=x

(7x + 6)(49x^2 - 42x + 36)

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x3 + 13x2 + 42x = x(x2 + 13x + 42) = x(x2 + 6x + 7x + 42) = x[x(x + 6) + 7(x + 6)] = x(x + 7)(x + 6)

4x2-42x+110 = (2x-10)(2x-11) when factored

5x - 42x + 5 = - 37 x +5

42x+35x-35x=42x it's leave 85 so it's change into a negative 42x-85 is the answer

It is 14*(3x + 2y)

It is: 42x+30x^2

-1/19=x

(7x + 6)(49x^2 - 42x + 36)

Collect the like terms;42x-23 = 940Add 23 to both sides;42x = 963Divide both sides by 42;x = 963/42

42x + 1 = 8x - 1Subtract 1 from each side:42x = 8x - 2Subtract 8x from each side:34x = -2Divide each side by 34:x = -2/34 = -1/17

x+5/7 = 11/6 Multiply all terms by 42: 42x+30 = 77 42x = 77-30 42x = 47 Divide both sides by 42: x = 47/42

-8 + 7x = x - 506x = -42x = -6