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Probably just one for the goats. Goats like to be in a small area. Depends on the type of land - lush grass, scrub, forested. If you plan to feed them just grains and feed then you can fit as many as you can house and pay for the feed. If you plan to feed them mostly browse then the moister and more weed heavy (less tall grass) the quicker they will develop issues with worms from eating in the same place and chewing closer to the ground where other goats have pooped. This process turbo charges the worms and quickly leaves the goats sickly and prone to other illnesses. 1 pair of goats per acre is fine in dry lush grassland and dense forested browse areas especially if you plan to supplement with grain and feed which is fed off the ground so they don't recycle and turbo charge the parasite worms. Good fecal count analysis and worm management will make this process more flexible.
Amplitude ratio to dB conversion:For amplitude of waves like voltage, current and sound pressure level:GdB = 20 log10(A2 / A1)A2 is the amplitude level.A1 is the referenced amplitude level.GdB is the amplitude ratio or gain in dB.dB to amplitude ratio conversion:A2 = A1 · 10(GdB / 20)A2 is the amplitude level.A1 is the referenced amplitude level.GdB is the amplitude ratio or gain in dB.
A decibel (dB) has meaning only when compared a quantity (P1, V1, or I1) with a reference (P0, V0, or I0). Since it is a ratio of two like quantities, it is dimensionless. For a power ratio, power gain = 10 * log10(P1/Po) in [dB]. For a voltage ratio, voltage gain = 20 * log10(V1/Vo) in [dB]. For example, when P1 = 100 * P0, the power gain = 10 * log10(100) [dB] = 20 dB.
there are 80 goats and 20 chickens.
Gain should be distributed in the ratio of 12:8 ie 3:2 so A gets 3/5 ie R180 and B gets R120.