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Assume that we're only looking at the hour and minute hand, and not the second hand. It doesn't specify which hands, and not all clocks have a second hand.

There are 360° in a circle, so the minute hand moves 6° per minute, and the hour hand moves 0.1° per minute.

The minute hand starts out at 0°, and the hour hand starts out at 150°, so we have the position functions of the two hands:

  • M(t) = 6*t
  • H(t) = t/10 + 150

t is the time (in minutes) after 5 o'clock. Now just find the value of t where H(t) - M(t) = 84 {it will first happen as the minute hand is approaching the hour hand}:

t/10 + 150 - 6*t = 84 ---> 66 = 5.9*t ---> t = 66/5.9 = 11.1864407 minutes. So the time is 11 minutes & 11.19 seconds after 5 o'clock.

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