If the lengths of the parallel sides are x and y units, and the height is h units, then the area = 1/2*(x + y)*h square units.
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Let's call the parallel sides A and B, and the distance between them as H. The area of the trapezium, or K, is (A+B)H/2. K = (A+B)H/2
Suppose you have a trapezium whose parallel sides (bases) are of lengths A and B units, and where the height is h units If you flip a trapezium over and append it to the original along one of the bases you will have a parallelogram whose base is A+B units in length and whose height is h units. So 2*Area of trapezium = Area of parallelogram = (A + B)*h
has two parallel sideshas four straight linesThe area of the trapezium is given by the following formula where a and b are the lengths of the parallel sides and h is the perpendicular distance between the parallel sides.
Suppose you have a trapezium whose parallel sides (bases) are of lengths A and B units, and where the height is h units If you flip a trapezium over and append it to the original along one of the bases you will have a parallelogram whose base is A+B units in length and whose height is h units. So 2*Area of trapezium = Area of parallelogram = (A + B)*h
The area of a trapezium is found because: 0.5*(sum of parallel sides)*height = area