Bollard pull is typically calculated using the formula: ( BP = \frac{(T \times V)}{33000} ), where ( BP ) is the bollard pull in pounds, ( T ) is the thrust in pounds, and ( V ) is the speed in knots. To convert bollard pull to horsepower (HP), you can use the formula: ( HP = \frac{BP \times V}{550} ), where ( V ) is in feet per minute. Thus, bollard pull and horsepower can be connected through their relationship with thrust and speed.
Power in horsepower (hp) can be calculated using the formula: [ \text{hp} = \frac{\text{Torque (lb-ft)} \times \text{RPM}}{5252} ] This formula relates torque (in pound-feet) and rotational speed (in revolutions per minute, RPM) to derive horsepower. Alternatively, for electrical power, it can be calculated as: [ \text{hp} = \frac{\text{Watts}}{746} ] where Watts is the power in watts.
max amps
To convert horsepower (hp) to cubic centimeters (cc), you typically use the formula that relates engine displacement to power output, although the exact conversion can vary based on engine design and efficiency. A rough estimate is that 1 hp is approximately equivalent to 15 cc in a gasoline engine. Therefore, 8.75 hp would be roughly equivalent to about 131.25 cc. However, this is a general estimate and actual displacement can vary significantly based on the specific engine.
No but the Pooler one does. If you don't know it check out the website: http://www.google.ca/search?hl=fr&source=hp&q=baby+food&meta=&aq=f&oq=&safe=strict It will tell you how.
Equal... in what sense? hp (horse-power) is a unit of power; 280 hp is more than 250 hp. An engine that works at a higher power can get more work done per time unit. Such an engine is also likely to use up more fuel - assuming the energy efficiency of both is similar.
wring out. (formula: 120x[opponent's current Hp/Opponent's Max Hp]
There is no such formula as the hp rating of an engine depends on many factors in addition to the cc size of the cylinders. There are approximations of this formula for various classes and designs of engine, but you have to remember that they only give rough estimates of hp and using such a formula for a different class or design of engine than it was intended for will give a completely incorrect answer.
285 hp.
what formula is used for calculate flow rate of pump vs kw
For a single-phase induction motor, allow 7 amps on a 240 v for a 1-HP motor. Therefore the formula is: current = 7 X HP x 240 / voltage
Yes, but not very fast.
93-95, 275 hp - 96-97, 285 hp
i have a 50 hp force on a 18 foot invader boat a i pull one just fine only shows problem when u have three or more on tube so have fun
Yes, with no problems at all.
To calculate the HP of a motor, you can use the formula: HP = (Watts x Efficiency) / 746 Where Efficiency is a typical value between 0.7 and 0.9. For a 3 amp motor, you will need to know the voltage to calculate the wattage and then convert it to HP using the formula above.
300 horse if it's a V8.
All depends on the weight that the 150 hp has to push, or pull, and the gearing.