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Let the sides be a,b,c,(opposite to BC,AC,AB): Let the angle be enclosed at vertex A.Let R be the length of the angle bisector.
The formula to find R is:

  • cb= R*R + ([{(c-b)(c-b)-2bc.(cos A-1)}^1/2]/c+b)^2.cb
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Q: What is the formula for getting the length of an angle bisector?
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