1/2 x BH
B = area of base
H = height
The two nets of a regular right triangular prism are surface area and volume.
The dimensions given do not support Pythagoras' theorem for a right triangular prism which will have a right angle triangle at each end
The lateral area [L] of a right prism with base perimeter [P] and height [h] is L=Ph.
Do you mean, what is the volume of a (right) triangular prism? Multiply the area of one end by the length of the prism.
To calculate the volume of a right triangular prism, first determine the area of the triangular base using the formula ( \text{Area} = \frac{1}{2} \times \text{base} \times \text{height} ) of the triangle. Then, multiply the area of the triangle by the prism's height (the length perpendicular to the base) using the formula ( \text{Volume} = \text{Area of base} \times \text{height of prism} ). This will give you the volume of the prism.
the defnition of find the surface area of triangular prism and cylinder
48 cm2
The two nets of a regular right triangular prism are surface area and volume.
In a general triangilar prism, none.In a right triangular prism, three pairs and one triplet.In a general triangular prism, none. In a right triangular prism, three pairs and one triplet.
The volume of a three-dimensional figure is the amount of space it encloses. The volume V of a triangular prism is the product of the area B of a base and the height h of the prism. (The bases are triangles. In a special case of a right triangular prism the bases are right triangles)
No, it is not.
bxh b=base h=height
The dimensions given do not support Pythagoras' theorem for a right triangular prism which will have a right angle triangle at each end
A triangular prism can have right angles. If the prism has two triangular ends, then each of the three 'sides' meets each of the ends at right angles.
It may be though it does not have to be.
The lateral area [L] of a right prism with base perimeter [P] and height [h] is L=Ph.
The lateral area [L] of a right prism with base perimeter [P] and height [h] is L=Ph.