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Let P(A) = 1/10; P(A) = probability of selecting one people on a Basketball team

P(B) = 1/35; P(B) = probability of selecting one people on a football team

P(C) = 1/10 = probability of selecting one people who plays in both teams

P(D) = probability of selecting from either team.

P(D) = P(A) + P(B) - P(C)

P(D) = 1/10 + 1/35 - 1/10

P(D) = 1/35 or 0.0286

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