a^(2) - b^(2) = ( a - b)( a + b)
NB Noter the different signs.
NNB Note the ADDITION of perfect squares ' a^(2) + b^(2) ' does NOT factor.
There is a formula for the "difference of squares." In this case, the answer is (6v + w)(6v - w)
It is the difference of two squares which is: (x+2y)(x-2y)
That looks simple enough for me; but if you want to factor it, you can use the formula for the difference of two squares.
There is a formula for the "difference of squares." In this case, the answer is (x2 - 5)(x2 + 5)
To factor the difference of squares, use the formula ( a^2 - b^2 = (a - b)(a + b) ). Identify ( a ) and ( b ) as the square roots of the two terms in the expression. For example, to factor ( 9x^2 - 16 ), recognize ( 9x^2 ) as ( (3x)^2 ) and ( 16 ) as ( 4^2 ), then apply the formula to get ( (3x - 4)(3x + 4) ).
There is a formula for the difference of two squares. The sum of two squares doesn't factor.
The formula to factor the difference of two squares, a2 - b2, is (a + b)(a - b).
The "difference of squares" has a formula. (11x + 1)(11x - 1)
The "difference of squares" has a formula. (3cd2 + 4ef)(3cd2 - 4ef)
There is a formula for the "difference of squares." In this case, the answer is (4x + 3)(4x - 3)
There is a formula for the "difference of squares." In this case, the answer is (3A + B)(3A - B)
There is a formula for the "difference of squares." In this case, the answer is (2x + 5)(2x - 5)
There is a formula for the "difference of squares." In this case, the answer is (6v + w)(6v - w)
There is a formula for the "difference of squares." In this case, the answer is (5b - 14c)(5b + 14c)
There is a formula for the "difference of squares." In this case, the answer is (5c - 14d)(5c + 14d)
There's a formula for the "difference of squares." (x + 1)(x - 1)
There is a formula for the "difference of squares." In this case, the answer is (3m + 13n)(3m - 13n)