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Formula to Find the Equity

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17y ago

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Will amox trk clv 875-125 treat bv Is so how many?

Amoxicillin/clavulanate (amox TRK CLV 875-125) is not typically used as a first-line treatment for bacterial vaginosis (BV). BV is usually treated with antibiotics such as metronidazole or clindamycin. If you suspect you have BV, it's best to consult a healthcare provider for appropriate diagnosis and treatment options.


What is the meaning of AU and BU when looking up the value of coins?

AU means "about uncirculated" and BU means bullion. BV stands for Bullion value and BU is the abbreviation for Brilliant Uncirculated.


Show how the period of oscillation relates to the velocity of the pendulum bob.?

Technically, in an ideal experiment, where there is lack of any opposing forces like air drag and friction, the period of oscillation of a pendulum only depends on the length of string (i.e, for r<<L). However, in presence of air drag, a force opposite to the velocity of the bob reduces the energy of oscillations, so it also changes the period of oscillations. acc to a law similar to stoke's law Fv = -bv where 'b' is a constant and depends on medium and the bob. So, the force acting on bob is the resultant of -w2x and -bv. this is how the period of oscillation depends on the velocity of pendulum bob.


What is 14 over 45 in simplest form?

1 over 3n kl j; bbvkbl bfj bnnj vkbk bfb l/bv kv vkd cn fkvc lh pkbopjl bnkop jonoo ko jn;[l lk k;pkjpn n lklkmlnm mnn


How to proof the distributive law in vectors?

If we're talking vectors in a vector space, then distributivity is taken as an axiom. We can prove it for vectors in Rn, therefore (partially) proving that our common notion of vectors actually satisfies the axioms of a vector space. Below, a and b are scalars and v and w are vectors. a(v+w) = a( (v1, ..., vn) + (w1, ..., wn) ) = a(v1+w1, ..., vnwn) = (a(v1+w1), ..., a(vn+wn)) = (av1+aw1, ... , avn+awn) = (av1, ..., avn) + (aw1, ..., awn) = av+aw (a+b)v = (a+b)(v1, ..., vn) = ((a+b)v1, ..., (a+b)vn) = (av1+bv1, ..., avn+bvn) = (av1, ..., avn) + (bv1, ..., bvn) = av+bv