this means that for every four feet of the ladders height you must set out one foot from the place you are working in order to be stable
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order of operations
One and four tenths.
one and four twelfths
If h is vertical height, b=horizontal distance from wall to bottom of ladder and l=lenght of ladder,we can say lsquared = hsquared + b squared. Now differentiate w.r.t. time t. 2l*dl/dt= 2h* dh/dt + 2b*db/dt =0 However this solution doesn't give exactly the same answer when one solves the problem geometrically or using simple pythagorus. For example ,if l=20m and b=12 m and h=16m and db/dt is 2m/s, I calculate dh/dt as !.5 m/s using calculus but 1.717 m/s using geometry or straight Pythagorus. Where is the fallasy inthe method using calculus? Ray Bevan
Rule one is to never believe anything unless you know it to be true. Rules two is to divide any issue into as many parts as possible for examination. Rule three is to find the easiest solution and work up to the most difficult. Rule four is to list every possible detail of a problem.