No.
d = a - 2bc
A formula is a statement. It's not a problem or an exercise to which a solution is needed.
An algorithm is the series of steps to solve problem, so you would be looking for the series of steps to solve a math problem.
to solve ax2 + bx + c use the quadratic formula: (-b +/-(b2 - 4ac))/2a. Programming this should be a doddle.
Generally,1. Convert parallel branches into series equivalents2. Solve for the total resistance3. Solve for individual voltages4. Solve for individual currents5. Solve for power
You can solve for resistance using the formula ( R = \frac{V^2}{P} ), where R is the resistance, V is the voltage, and P is the power. By rearranging the formula, you can solve for resistance by dividing the square of the voltage by the power.
To convert power from 1500 watts at 240V to 375 watts at 12V, you can use the formula P=VI (power = voltage * current). First, calculate the current at 240V by rearranging the formula to I=P/V. Then, input the current calculated at 240V into the formula to solve for the current at 12V. Finally, rearrange the formula P=VI to solve for the power at 12V using the current calculated in the previous step.
11 and 11. In general, you can write an equation (or two equations), and solve with the quadratic formula, to solve this type of questions.
You can't solve a formula with no equals sign
No.
every thing will not go to much with the amount of power each branch has
To find the current in the circuit, you can use the formula: Power = Current^2 * Resistance. Given the values, you can rearrange the formula to solve for current: Current = sqrt(Power / Resistance). Plugging in the values, you get Current = sqrt(2 / 30) which simplifies to approximately 0.27 amperes.
d = a - 2bc
A formula is a statement. It's not a problem or an exercise to which a solution is needed.
An algorithm is the series of steps to solve problem, so you would be looking for the series of steps to solve a math problem.
900 and divide10 with the power of four solve it = 90