graph G(x)=[x]-1
- 2 makes this zero and provides the vertical asymptote. So, from - infinity to - 2 and from - 2 to positive infinity
The domain is anything you want it to be. You could define the domain to be integer values only, or it could be {-3, -2.5, .2, 0, sqrt(7), 9}.
It is the straight line through the points (0, -1) and (1, 0).
if your point if 3/4 and your line is y=2x+4 then yes 3/4 does lie on this graph. any point in existence lies on this graph because its domain is all real numbers
graph G(x)=[x]-1
- 2 makes this zero and provides the vertical asymptote. So, from - infinity to - 2 and from - 2 to positive infinity
The domain is anything you want it to be. You could define the domain to be integer values only, or it could be {-3, -2.5, .2, 0, sqrt(7), 9}.
Find the domain of the relation then draw the graph.
It is the straight line through the points (0, -1) and (1, 0).
You cannot calculate the domain of a funciton, unless you put more conditions onto what you are asking. If you are asking for the domain of the function when it is below the x-axis of its graph, the domai wold be 1.33333 (4/3)<x<1.66666 (5/3)
It is 11/3
So, if we have the equation: F(x) = x^2 + 3 this is a function in terms of x, another way to look at this same problem is to write it as: y= x^2 +3. This function may be graphed if that is what you are looking for, the graph will be of a parabola and then the graph will be shifted from the origin up 3 from the origin.
if your point if 3/4 and your line is y=2x+4 then yes 3/4 does lie on this graph. any point in existence lies on this graph because its domain is all real numbers
this month(April) - trailer on FX
A graph of a ^2 looks like a capital "U" and a graph of a ^3 looks like "U" but the left side of the "U" is flipped over the x-axis.
If you want to ask questions about the "following", then I suggest that you make sure that there is something that is following.