Integers that end in zero have an ambiguous number of significant digits: it is not possible to tell whether the number has been obtained by rounding to the nearest unit or nearest ten.
Therefore, if you assume that the measure has been rounded to the nearest ten, the greatest possible error is 5 cm.
.05
0.05 metres or 5 cm.
The greatest possible error should be one half of the smallest unit used. The smallest unit used here is a tenth of a metre - or 100 cm. So the greatest error is 50 centimetres. Unfortunately, measurements are often given to spurious levels of accuracy.
42.25 cm2
20 cm x 20 cm x 20 cm = 8,000 cm3
0.05 cm.
.05
0.05 metres or 5 cm.
for example you use a beam balance to find the mass of a rock sample for a science lab. you read the scale as 3.8g. what is your greatest possible error? well the rocks mass was measured to the nearest 0.1g, so the greatest possible error is one half of 0.1g he's right but here's the definition: one half of the unit of measurement to which the measure is being rounded. EX. the greatest possible answer of 3g is 1.5g If you have 3 cm, you are measuring to the nearest cm, so the greatest possibel error would be .5 cm.
If the number of significant digits is correct, this measurement should be between 4.6 and 4.8 and thus have a possible maximum error of 0.1.
The greatest possible error should be one half of the smallest unit used. The smallest unit used here is a tenth of a metre - or 100 cm. So the greatest error is 50 centimetres. Unfortunately, measurements are often given to spurious levels of accuracy.
If measured top the nearest centimetre then the answer is 0.5 cm.
It is half the place value of the last digit that is given. In this case, it is + or -0.05m = + or - 5 cm.
first you must find the precision. that is the smallest possible unit of the smallest measurement. in this case the smallest measurement is 5/10ths. the smallest possible unit is 1/10. so 1/10 is the precision. to find the greatest possible error you have to multiply the precision (1/10) by 1/2. and you get 1/20. the greatest possible error is 1/20. another example: find the greatest possible error of both 6 and 3.214. for 6 the smallest unit would be 1 because you can go lower than one without going to the next unit down. so we then take one and multiply it by 1/2. one half is also 0.5. 1 multiplied by 1/2 is 1/2, therefore, the greatest possible error of 6 is 1/2 or 0.5. for the next number take the smallest unit of 214/1000, which is what .214 is. the smallest measurement would be 1/1000. that is our precision. the greatest possible error is one half (1/2) of the precision, or, 1/1000 x 1/2, which equals 1/2000. the greatest possible error of 3.214 is 1/2000. it's kind of confusing. i hope this helped. first it helps to understand the precision. then from there the gpe is half of the precision.
42.25 cm2
6
This is a two step problem: First you must find the Greatest Possible Error (GPE)? To find the greates possible error, you must acknowledge the significant place value. In this case because it is measured to 3cm the answer is 1cm. The GPE is half of 1cm which is 0.5cm. Second the percent of error is a ratio of the GPE/Original measurement. In this case it is 0.5/3 is 0.16666666667 therefore the answer is: approximately 16.67% or 16.7% or 17%