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The greatest six-digit number is formed by maximizing each digit while adhering to the condition that the thousands place is twice the digit in the tens place. Let the tens place be represented by ( x ); thus, the thousands place will be ( 2x ). The maximum digit for ( x ) that allows ( 2x ) to remain a single digit is 4 (since ( 2 \times 4 = 8 )). Therefore, the greatest six-digit number is 986,400, where the thousands place (8) is twice the tens place (4).

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1mo ago

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What are the greatest and least 6-digit numbers in which the digit in the thousands place is twice the digit in the tens place?

Oh, what a happy little question! The greatest 6-digit number where the digit in the thousands place is twice the digit in the tens place is 986,432. And the smallest 6-digit number following the same rule is 164,823. Isn't it wonderful how numbers can dance together in such a harmonious way?


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