Well, for my part, I just recently counted past (decimal) "one and a half million" ("1,519,616" to be "exact"), and am still counting (and I have relied very little on writing down where I am as I count). I am actually counting (at present) in a base that I could be called "balanced base-sixty-four" or "quadrosexagesimal"; and - in that base - the number would be "6¯d00". In "base thirty-two" or "duotrigesimal", it would be "1ec00". I started this particular counting project about a year and a half ago now, and - God willing - will keep counting at least until I reach (decimal) 33,554,432 - which is "1,00000" in duotrigesimal or "20000" in quadrosexagesimal.
(By the way the over-bar "¯" indicates a negative rather than positive value, the symbols "c", "d", and "e" represent decimal "12", "13", and "14" respectively. So, for example, "¯d" represents decimal: "negative 13". Also, in base sixty-four and base thirty-two, each "place" to the left represents a power of decimal "64" and "32", respectively. Therefore, thequadrosexagesimal value: " 6 ¯d 0 0 " equals decimal 6*64^3 - 13*64^2; and the duotrigesimal: " 1 e c 0 0 " equal decimal 1*32^4 + 14*32^3 + 12*32^2. Furthermore, quadrosexagesimal "20000" equals 2*64^4 and duotrigesimal "1,00000" equals 32^5.)
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There is no highest whole number because they go on for ever.
i it 90
The longest number that would also be the smallest would be the highest number counted to just made into its negative form.
You can never get to grahams number. Grahams number can never be specified. It is the biggest number ever counted.
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