The hypotenuse of a right triangle with legs 12 inches and 16 inches is: 20 inches.
It's 6,40312. 4²+5²= hypotenuse ² 16+25=hypotenuse ² 41=hypotenuse ² |√ 6,40312=hypotenuse
If the hypotenuse (c) on a 30-60-90 triangle is six units, the lengths of the two legs are:a = 3b = 5.196
The legs of a right triangle have the same length and the hypotenuse is 30 ft, each leg would be of length 21.21 ft.
If it is a right angle isosceles triangle then by using Pythagoras' theorem its hypotenuse is 30 times the square root of 2
The hypotenuse of a right triangle with legs 12 inches and 16 inches is: 20 inches.
It's 6,40312. 4²+5²= hypotenuse ² 16+25=hypotenuse ² 41=hypotenuse ² |√ 6,40312=hypotenuse
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If the hypotenuse (c) on a 30-60-90 triangle is six units, the lengths of the two legs are:a = 3b = 5.196
c2 = a2 + b2, where c is the hypotenuse, and a and b are the other two sides. c2 = 162 + 302 c2 = 1156 √c2 = √1156 c = 34
The legs of a right triangle have the same length and the hypotenuse is 30 ft, each leg would be of length 21.21 ft.
If it is a right angle isosceles triangle then by using Pythagoras' theorem its hypotenuse is 30 times the square root of 2
To get the hypotenuse you need to square the twoo legs and add them together. Then that final answer, you find the square root of, and that's your FINAL answer. If both legs are 4, then you square four: 42 + 42 = 16+16 = 32 The square root of 32 is: about 5.65 5.65 is the length of your hypotenuse. Hope this helps -FlapJack
The formula to find the hypotenuse of a right triangle is a2+b2=c2. c being the hypotenuse, a and b being the legs. So, 42+32=c2. 16+9=c2. 25=c2. c=5. The hypotenuse is 5.
Using Pythagoras' theorem for a right angle triangle its hypotenuse length is 78 in.
The hypotenuse of a right triangle with legs of 8 and 10 is: 12.81
The hypotenuse of a triangle with legs of 35 and 68 is: 76.48