Given an improper fraction of the from x/y where x and y are integers and x>=y>0,let x = q*y + r [q is the quotient and r the remainder when x is divided by y].
Then x/y = (q*y + r)/y = q + r/y
For mathematically inclined people who wish to cover all bases for the assumptions that x>=y>0
If y is negative, then the numerator and denominator of the fraction can be multiplied by -1 to give an equivalent fraction; except that now y > 0.
If 0 < x < y then q = 0 so that x/y is a proper fraction and so there is no mixed number.
If x < 0 then swap with -x (which will be >0), calculate the mixed number and put a negative sign in front of the answer.
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If you are using the same number, then the improper fraction and mixed number are equal.
Improper Fraction.
43 is an integer, not an improper fraction nor a mixed number.
A mixed number can be changed into an improper fraction
First you would want to change the mixed number to an improper fraction. Then you can subtract