Best Answer

Numbers are n and n + 2, so product = n2 + 2n and sum = 2n + 2.

ie n2 + 2n + 1 = 6n + 6

or n2 - 4n - 5 = 0

Factors are (n + 1)(n - 5) making n = 5 and the integers 5 & 7.

Check: 5 x 7 = 35; 5 + 7 = 36. OK

There is also an answer of n = -1, making the integers -1 and 1, product being -1 and sum zero.

Q: What is the integer if the product of two consecutive odd integers is one less than three times their sum?

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The let statement is: let the smallest of the three integers be x.

the product of two consicutive multiple of three integers

There is no set of three consecutive odd or even integers whose sum is negative 31.

The integers are 53, 55 and 57.

They are 14, 16 and 18.

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The sum of three consecutive integers is -72

The integers are 5 and 7.

9240 is the product of the three consecutive integers 20, 21, and 22.

There must be three consecutive integers to guarantee that the product will be divisible by 6. For the "Product of three consecutive integers..." see the Related Question below.

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This would be impossible - since the mean of the three integers would have to be an integer, and if you divide -56 by 3, you do not get an integer.

The let statement is: let the smallest of the three integers be x.

the product of two consicutive multiple of three integers

270

Not sure what thress is. If three, then there is no answer since the sum (or product) of any three consecutive integers must be divisible by 3.

There is no set of three consecutive odd or even integers whose sum is negative 31.