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Q: What is the integral of e - kx n?
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Integration of e e?

Writing equations in questions is problematic - some symbols regularly get eliminated.The integral of e to the power x is: e to the power x + C If your expression contains no variables, for example e times e, or e to the power e, then the entire expression is a constant; in this case, the integral is this constant times x + C.


What is the integral of e raised to x squared?

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What is the period of the wave?

Given a wave f(x, t), we call period T the interval of time we need to wait before the form of the wave is repeated. Obviously, we must choose a constant x and observe the wave passing trough it.For exemple, for f(x, t) = ei(kx - wt) it's f(x, t + T) = ei(kx - w(t + T)), so that we have 0 = f(x, t + T) - f(x, t) = ei(kx - wt) (e-iwT - 1) → e-iwT = 1 → T = n 2π/w, with n element of Z. If we are considering two near peaks of f (that is a good way to define T) n = 1, and we have the famous T = 2π/w.


What is the answer of 1 divide by x square?

What do you mean? As this is a calculus question, I presume that you are asking for a derivative or integral The derivative of any function of the form ƒ(x) = a * x ^ n is ƒ'(x) = a * n * x ^ (n-1) The integral of any function of the form ∫ a*x ^ n is a / (n+1) * x ^ (n+1) + C Your function that you gave is 1 / x^(2) which is equal to: x^(-2) Thus the derivative is: -2 * x^(-3) And the integral is: -x^(-1) + C


How do you integrate xe power x?

Use integration by parts. integral of xe^xdx =xe^x-integral of e^xdx. This is xe^x-e^x +C. Check by differentiating. We get x(e^x)+e^x(1)-e^x, which equals xe^x. That's it!