If you mean: 2x-3y = 50 then y = 2/3x-50/3 whereas the slope is 2/3 and the y intercept is -50/3
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To find the intercept of the line 2x - 3y + 50, we need to set one of the variables to zero. The x-intercept occurs when y is zero, so we can solve for x by setting y=0: 2x - 3(0) + 50 = 0. Simplifying, we get 2x + 50 = 0, which gives x = -25. Therefore, the intercept is (-25, 0).
Slope= -2/5 y-intercept is 20 x-intercept is 50
Without an equality sign and not knowing some of the plus or minus values of the given terms it can't be considered to be a straight line equation. But if you mean: y = 12x-3 a given point of (5, 0) Then the perpendicular equation is: y = -1/12x+5/12 whereas -1/12 is the slope and 5/12 is the y intercept
It depends on what you are looking for regarding y=50-5t. Try to include more details in the future.The y intercept is y=50The x-intercept is:t=10There are no critical points, so there are no maximum or minimum functions.The function is linear, with a slope of -5, therefore y`= -5The integral is:∫ 50-5t dt =50t - 5/2t2 + C
50 + 50 + 94 + 94 = 288
20 + 50 + 20 + 10 = 50 = 150