57 divided by 3 is 19. (Any number in which all the digits add up to equal a number divisible by 3 is divisible by 3. 5+7=12 which is divisible by 3.) And since 57 is divisible by more numbers than just 1 and itself it is a composite number.
99
numbers that are divisible by 4 is either: 4n or numbers in which the number formed by last two digits are divisible by 4
All whole numbers are divisible by 1. Numbers are divisible by 2 if they end in 2, 4, 6, 8 or 0. Numbers are divisible by 3 if the sum of their digits is divisible by 3. Numbers are divisible by 4 if the last two digits of the number are divisible by 4. Numbers are divisible by 5 if the last digit of the number is either 5 or 0. Numbers are divisible by 6 if they are divisible by 2 and 3. Numbers are divisible by 9 if the sum of their digits is equal to 9 or a multiple of 9. Numbers are divisible by 10 if the last digit of the number is 0.
It would probably refer to a digit that is a prime number, or a composite number. Note that mathematicians normally talk about prime and composite NUMBERS, not individual digits.
The largest single-digit composite is nine (9).
999
To know if a number is composite without listing its factors, you can use these rules:All numbers that end with 2, 4, 6, 8, and 0 (even numbers) are divisible by 2.If the sum of the digits in a number is divisible by 3, the number is divisible by 3.If the last two digits are divisible by 4, the number is divisible by 4.All numbers that have 5 in the one's place are divisible by 5.If a number is divisible by 2 AND is divisible by 3, it is divisible by 6.If the last 3 digits of a number are divisible by 8, the number is divisible by 8.If the sum of the digits of number is divisible by 9, the number is divisible by 9.If a number ends wuth 0, the number is divisible by 10.
It's divisible by three, since the sum of its digits is divisible by three. So it's composite.
Both numbers are composite numbers. Using the rules of divisibility, 2312 is composite because it is an even number that ends with 0, 2, 4, 6, or 8. 3819 is composite because the sum of its digits equal 21, a number that is divisible by 3, so the number itself is divisible by 3.
not a prime number as itβs divisible by 1, 63, 3, and 21
57 divided by 3 is 19. (Any number in which all the digits add up to equal a number divisible by 3 is divisible by 3. 5+7=12 which is divisible by 3.) And since 57 is divisible by more numbers than just 1 and itself it is a composite number.
No. 26 for instance the sum of the digits is 8 but not divisible by 4. 32 the sum of the digits is 5 but divisible by 4 The rules for some other numbers are 2 all even numbers are divisible by 2 3 The sum of the digits is divisible by 3 4 The last 2 numbers are divisible by 4 5 The number ends in a 0 or 5 6 The sum of the digits is divisible by 3 and is even 7 no easy method 8 The last 3 numbers are divisible by 8 9 The sum of the digits is divisible by 9
99
Of the ten digits, 0 is the only one that is divisible by 9.
57 divided by 3 is 19. (Any number in which all the digits add up to equal a number divisible by 3 is divisible by 3. 5+7=12 which is divisible by 3.) And since 57 is divisible by more numbers than just 1 and itself it is a composite number.
All numbers that are divisible by 6 are even numbers whose digits add up to 3 or a multiple of 3. Example : 284 is not wholly divisible by 6 as although it is even, its digits total 2 + 8 + 4 = 14 which is not divisible by 3. 282 is divisible by 6 as it is even and its digits total 12 which is divisible by 3.