There is none. For if there was such a number, X, then X+2 would also be even and would be larger!
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umm...455000?
For this type of "the largest number which..." questions, you need to advance from left to right, using the largest possible digit in each case. For the first two digits, that would be 9, for the third digit (the right-most digit), the largest digit which will make this possible is an 8.
The largest possible number for a remainder is 1 less than the number of the divisor, so it is 5.
It's an even number, so it has to end with the 6.We need it as big as possible, so the largest number left over goes first, which is the 7. Finally, the 5 goes in the tens place to get 756.
No, in order for the number to be even, the last number must be a multiple of 2. It doesn't matter what the largest number is as long as the last number is a multiple of two.