Where the a^b means a raised to the b power:
1111 = 2^3 + 2^2 + 2^1 + 2^0 = 8 + 4 + 2 + 1 = 15
There are 16 decimal numbers that can be represented by 4-bits.
An integer is any whole number. For example, 4, 16, -8 are all integers. There is no decimal part. Obviously, there is no "maximum number" as these numbers continue up to infinity.
x+3 and x+4 would be consecutive integers.
the number 4 is an integer.
11111111; 255 or 1+2+4+8+16+32+64+128=255 Answer 255 There are 8 bits in a byte when all are set to zero (turned off) then the value is 0. When all of the bits in a byte are set to 1 (turned on) you get the largest value that a byte holds which is 255.
There are 16 decimal numbers that can be represented by 4-bits.
4
A total of 65,536 items can be represented with 16 bits. A total of 64 items can be represented with 6 bits and 1024 items with 64 bits.
NO, it is a decimal that can be represented as the fraction 1/4 but can never be written as n integer.
2
3 is the largest.
integer data type consumes memory of 4 bytes or 32 bits
4
24 = 16
4
A nibble (also known as a nybble or nyble) can represent half a character(two nibbles are needed for a valid ASCII character). A nibble is made up of 4 bits and those 4 bits are usually represented by a single hexadecimal value. 4 bits only allows for 16 combinations, 8 bits allows for 255. An ASCII character is represented by two hexadecimal characters, which is the same as 8 bits or two nibbles.
The set of positive integers is {1, 2, 3, 4, 5, ...}. Because the values approach positive infinity there is no largest positive integer. If you pick any positive integer, you can always create a larger one by simply adding 1 to it. So there can be no largest positive integer.